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6x^2-11x=17
We move all terms to the left:
6x^2-11x-(17)=0
a = 6; b = -11; c = -17;
Δ = b2-4ac
Δ = -112-4·6·(-17)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-23}{2*6}=\frac{-12}{12} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+23}{2*6}=\frac{34}{12} =2+5/6 $
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